ACSL Assembly, or AAL runs on a computer with memory, and each of its variables is a number from -999999 to 999999 (inclusive).

Mathematical operations are done mod 1,000,000. For example 999,995 + 10 = 5. Division is similar, but decimals are ignored, not rounded. For example, 14/5 = 2.8 ->2, not 3.

Execution starts at the first line and continues sequentially, besides branches, until the END command.

The result of each operation is stored in memory, called the ACC (accumulator).

OPCODE LOC

OPCODE are various functions, and LOC is basically a variable, or immediate data, so every command is built t=liek that.

LOAD A -> Loads A into the ACC LOAD =123 -> Loads 123 into the ACC STORE VARIABLE -> Stores the value in the ACC into variable ADD A -> ACC += A (mod 1,000,000) SUB B -> ACC -= B (mod 1,000,000) MULT C -> ACC *= C (mod 1,000,000) DIV D -> ACC /= D (only the integer part of the result is used)

BE Place -> goes to a line given the ACC == 0. BG Place -> if ACC > 0, goes to a given line BL Place -> if ACC < 0, go to a given line BU Place -> goes to Place no matter what means "branch unconditionally" END -> program ends. LOC is ignored

READ number -> Reads an integer (mod 1,000,000) into LOC PRINT var -> Prints var word DC number -> makes word = number as a constant

After this program is executed, what's the final value in location TEMP?

TEMP DC 0 ADC 8 BDC -2 CDC 3 LOAD B MULT C ADD A DIV B SUB A STORE TEMP

ACC:

-2

(-2 * 3) = -6

-6 + 8 = 2

2/-2 = -1

-1 - 8 = -9

TEMP = -9

So, the answer to this problem is -9. The final TEMP value is -9.